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Chess Problem 1996d1h201

Michael McDowell & BDS

4th HM., feenschach, 1996

2*3R*3B4/8/8/7*3r/5*3b2/4*3RB2/7k/3K4

H=2
2 solutions
PAOs e3, c8; h5
VAOs d8; f4 

1.VAd6 PAc1 2.PAe5 VAc7=
1.PAh7 VAb6 2.VAh6 PAh8=

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